Advertisements
Advertisements
प्रश्न
Find the perimeter and area of the quadrilateral ABCD in which AB = 17 cm, AD =9 cm, CD = l2cm, ∠ACB = 90° and AC=l5cm.
Advertisements
उत्तर
The sides of a quadrilateral ABCD in which AB = 17 cm, AD = 9 cm, CD = 12 cm, ∠ACB = 90° and AC = 15 cm
Here, By using Pythagoras theorem
`BC=sqrt(17^2-15^2) = sqrt(289-225)=sqrt64=8cm`
Now, area of ΔABC=`1/2xx8xx15=60cm^2`
For area of Δle ACD,
Let a = 15 cm, b = 12 cm and c = 9 cm
Therefore, S =`(15+12+9)/2=36/2=18cm`
Area of ACD =`sqrt(s(s-a)(s-b)(s-c))`
`=sqrt(18(18-15)(18-12)(18-9))`
`=sqrt(18xx18xx3xx3)`
`=sqrt((18xx3)^2)`
`=54cm^2`
∴ Thus, the area of quadrilateral ABCD = `60 + 54 = 114 cm^2`
APPEARS IN
संबंधित प्रश्न
Radha made a picture of an aeroplane with coloured papers as shown in the given figure. Find the total area of the paper used.
A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field.
Find the area of a quadrilateral ABCD is which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side is
In the given figure, the ratio AD to DC is 3 to 2. If the area of Δ ABC is 40 cm2, what is the area of Δ BDC?
A park is in the shape of a quadrilateral. The sides of the park are 15 m, 20 m, 26 m and 17 m and the angle between the first two sides is a right angle. Find the area of the park
The length of each side of an equilateral triangle having an area of `9sqrt(3)`cm2 is ______.
The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 9 paise per cm2 is ______.
The area of the equilateral triangle is `20sqrt(3)` cm2 whose each side is 8 cm.
In a triangle, the sides are given as 11 cm, 12 cm and 13 cm. The length of the altitude is 10.25 cm corresponding to the side having length 12 cm.
