Advertisements
Advertisements
प्रश्न
Find the area of a rhombus whose perimeter is 80 m and one of whose diagonal is 24 m.
Advertisements
उत्तर
Given that,
Perimeter of rhombus = 80m
Perimeter of rhombus = 4 × side
⇒ 4a = 80
⇒ a = 20m
Let AC = 24 m
∴ OA =`1/2AC=1/2xx24=12m`
In ΔAOB
`OB^2=AB^2-OA^2`
`⇒OB=sqrt(20^2-12^2)`
`sqrt(400-144)`
`sqrt(256)=16m`
Also BO = OD
[Diagonal of rhombus bisect each other at 90°]
∴ BD = 20B = 2 ×16 = 32 m
∴Area of rhombus = `1/2`×32×24=`384𝑚^2`
[∵Area of rhombus = 12×𝐵𝐷×𝐴𝐶]
APPEARS IN
संबंधित प्रश्न
A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field.
Area of PQRS = Area of PQR + Area of ΔPQS = (6+9.166)𝑐𝑚2=15.166𝑐𝑚2
The perimeter of a triangullar field is 144 m and the ratio of the sides is 3 : 4 : 5. Find the area of the field.
The sides of a triangular field are 325 m, 300 m and 125 m. Its area is
The sides of a triangle are 50 cm, 78 cm and 112 cm. The smallest altitude is
The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side is
The base and hypotenuse of a right triangle are respectively 5 cm and 13 cm long. Its area is ______.
The lengths of the sides of Δ ABC are consecutive integers. It Δ ABC has the same perimeter as an equilateral triangle with a side of length 9 cm, what is the length of the shortest side of ΔABC?
A land is in the shape of rhombus. The perimeter of the land is 160 m and one of the diagonal is 48 m. Find the area of the land.
The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is ______.
