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A hand fan is made by stitching lo equal size triangular strips of two different types of paper as shown in Fig. 12.28. The dimensions of equal strips are 25 cm, 25 cm and 14 cm. Find the area of each type of paper needed to make the hand fan.
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Given that the sides of ΔAOB are
AO = 24 cm
OB = 25 cm
BA = 14 cm
Area of each equal strips = Area of Δle AOB
Now, for area of ΔAOB
Perimeter of ΔAOB
Let 2s = AO + OB + BA
`⇒s=1/2(AO+OB+BA)`
`=1/2(25-25-14)=32 cm`
∴ЁЭР╡ЁЭСж ЁЭСвЁЭСаЁЭСЦЁЭСЫЁЭСФ ЁЭР╗ЁЭСТЁЭСЯЁЭСЬЁЭСЫ′ЁЭСаЁЭСУЁЭСЬЁЭСЯЁЭСЪЁЭСвЁЭСЩЁЭСОЁЭСТ
ЁЭР┤ЁЭСЯЁЭСТЁЭСО ЁЭСЬЁЭСУ (ΔЁЭР┤ЁЭСВЁЭР╡)=`sqrt(s(s-ao(s-ob)s-ba))`
`=sqrt(32(32-25)(32-25)(32-14))`
`=sqrt(32(7)(4)(18))`
`=168 cm^2`
∴ Area of each type of paper needed to make the hand fan = 5 ×(ЁЭСОЁЭСЯЁЭСТЁЭСО ЁЭСЬЁЭСУ ΔЁЭР┤ЁЭСВЁЭР╡)
= 5 × 168
= `840 cm^2`
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