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प्रश्न
Find the area of a parallelogram given in figure. Also find the length of the altitude from vertex A on the side DC.

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उत्तर
Let the sides of a triangle BCD are a = 12 cm, b = 17 cm and c = 25 cm and altitude of a parallelogram is h.
Area of parallelogram, ABCD = 2(Area of triangle BCD) ...(I)
Now, semi-perimeter(s) of triangle BCD will be:
`s = (a + b + c)/2`
= `(12 + 17 + 25)/2`
= `54/2`
= 27 cm
Area of triangle BCD = `sqrt(s(s - a)(s - b)(s - c))` ...[By Heron’s formula]
= `sqrt(27(27 - 12)(27 - 17)(27 - 25))`
= `sqrt(27 xx 15 xx 10 xx 2)`
= `sqrt(9 xx 3 xx 3 xx 5 xx 5 xx 2 xx 2)`
= 3 × 3 × 5 × 2 cm2
= 90 cm2
So, area of parallelogram ABCD = 2 × Area of triangle BCD
= 2 × 90 cm2
= 180 cm2 ...(II)
As, Area of parallelogram ABCD = Base × Altitude
80 = DC × h
180 = 12 × h
h = `180/12`
h = 15 cm
Therefore, the area of parallelogram is 180 cm2 and the length of altitude is 15 cm.
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