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प्रश्न
The perimeter of an isosceles triangle is 42 cm and its baše is (32) times each of the equal sides. Find the length of each side of the triangle, area of the triangle and the height of the triangle.
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उत्तर
Let ‘x’ be the measure of each equal sides
∴ Base =`3/2x`
`∴x + x + 3/2x= 42 ` [∵ Perimeter = a + b + c = 42 cm]
`⇒7/2x=42 `
`⇒x= 12cm`
∴Sides are a = x = 12 cm
b = x = 12 cm
`c=x=3/2(12)cm = 18 cm`
By heron’s formulae
∴ Area of triangle =`sqrt(s(s-a)(s-b)(s-c)) cm^2`
=`sqrt(21(9)(9)(21-18)cm^2)`
=`sqrt((21)(9)(9)(3))cm^2`
=`71.42cm^2`
`∴ Area of triangle = 71.42 cm^2`
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