मराठी

The Perimeter of an Isosceles Triangle is 42 Cm and Its BašE is (32) Times Each of the Equal Sides. Find the Length of Each Side of the Triangle, Area of the Triangle and the Height of the Triangle.

Advertisements
Advertisements

प्रश्न

The perimeter of an isosceles triangle is 42 cm and its baše is (32) times each of the equal sides. Find the length of each side of the triangle, area of the triangle and the height of the triangle.

Advertisements

उत्तर

Let ‘x’ be the measure of each equal sides

∴ Base =`3/2x`

`∴x + x + 3/2x= 42 `      [∵ Perimeter = a + b + c = 42 cm]

`⇒7/2x=42 `

`⇒x= 12cm`

∴Sides are a = x = 12 cm

b = x = 12 cm

`c=x=3/2(12)cm = 18 cm`

By heron’s formulae

∴ Area of triangle =`sqrt(s(s-a)(s-b)(s-c)) cm^2`

=`sqrt(21(9)(9)(21-18)cm^2)`

=`sqrt((21)(9)(9)(3))cm^2`

=`71.42cm^2`

`∴ Area   of triangle = 71.42 cm^2`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 17: Heron’s Formula - Exercise 17.1 [पृष्ठ ८]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 9
पाठ 17 Heron’s Formula
Exercise 17.1 | Q 10 | पृष्ठ ८

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×