हिंदी

A Car is Moving with a Uniform Velocity 30 Ms-1. It is Stopped in 2 S by Applying a Force of 1500 N Through Its Brakes. Calculate the Following Values : the Change in Momentum of Car.

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प्रश्न

A car is moving with a uniform velocity 30 ms-1. It is stopped in 2 s by applying a force of 1500 N through its brakes. Calculate the following values : The change in momentum of car.

योग
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उत्तर

Initial velocity, u = 30 m/s

Final velocity, v = 0

Time, t = 2s

Force, F = 1500 N

Here, a = (v - u)/t = (0 - 30)/ 2 = - 15 ms-2. Here, negative sign indicates retardation.

Now, F = ma.

Or, m = F/a = (1500/ 15) = 100 kg.

Change in momentum = Final momentum - Initial momentum

Or, Δp = m (v - u)

Or, Δp = 100 (0 - 30)

Or, Δp = 3000 kg m/s-1

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अध्याय 3: Laws of Motion - Exercise 3 (C) [पृष्ठ ७०]

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सेलिना Concise Physics [English] Class 9 ICSE
अध्याय 3 Laws of Motion
Exercise 3 (C) | Q 13.1 | पृष्ठ ७०

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