Advertisements
Advertisements
प्रश्न
A car is moving with a uniform velocity 30 ms-1. It is stopped in 2 s by applying a force of 1500 N through its brakes. Calculate the following values : The change in momentum of car.
Advertisements
उत्तर
Initial velocity, u = 30 m/s
Final velocity, v = 0
Time, t = 2s
Force, F = 1500 N
Here, a = (v - u)/t = (0 - 30)/ 2 = - 15 ms-2. Here, negative sign indicates retardation.
Now, F = ma.
Or, m = F/a = (1500/ 15) = 100 kg.
Change in momentum = Final momentum - Initial momentum
Or, Δp = m (v - u)
Or, Δp = 100 (0 - 30)
Or, Δp = 3000 kg m/s-1
APPEARS IN
संबंधित प्रश्न
Two blocks A and B of mass mA and mB , respectively, are kept in contact on a frictionless table. The experimenter pushes block A from behind, so that the blocks accelerate. If block A exerts force F on block B, what is the force exerted by the experimenter on block A?
Find the reading of the spring balance shown in the following figure. The elevator is going up with an acceleration g/10, the pulley and the string are light and the pulley is smooth.
Two balls A and B of masses m and 2 m are in motion with velocities 2v and v, respectively. Compare:
(i) Their inertia.
(ii) Their momentum.
(iii) The force needed to stop them in the same time.
State Newton's second law of motion. Under what condition does it take the form F = ma?
A pebble is dropped freely in a well from its top. It takes 20 s for the pebble to reach the water surface in the well. Taking g = 10 m s-2 and speed of sound = 330 m s-1. Find : The time when echo is heard after the pebble is dropped.
What do you mean by linear momentum of a body?
State Newton's second law of motion. Is Newton's first law of motion contained in Newton's second law of motion?
What do you mean by the conservation of momentum? Briefly, explain the collision between two bodies and the conservation of momentum.
A metre scale is moving with uniform velocity. This implies ______.
Figure shows (x, t), (y, t ) diagram of a particle moving in 2-dimensions.
|
|
 (b) |
If the particle has a mass of 500 g, find the force (direction and magnitude) acting on the particle.
