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प्रश्न
A ball hits a wall horizontally at 6.0 m s-1. It rebounds horizontally at 4.4 m s-1. The ball is in contact with the wall for 0.040 s. What is the acceleration of the ball ?
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उत्तर
We have to find the value of uniform acceleration.
We have:
Initial velocity (u) = 6 m/s
Final velocity is in opposite direction to that of initial velocity (v) = –4.4 m/s
Time taken (t) = 0.04 s
Acceleration :
`a = "υ-u"/t`
Put the values in the above equation to get the value of acceleration .
`a = "-4.4-6"/0.04`
= `10.4/0.04`
= `-260 "m/s"^2`
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