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∫ 6 X − 5 √ 3 X 2 − 5 X + 1 D X - Mathematics

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प्रश्न

\[\int\frac{6x - 5}{\sqrt{3 x^2 - 5x + 1}} \text{ dx }\]
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उत्तर

\[\text{ Let I }= \int\frac{6x - 5}{\sqrt{3 x^2 - 5x + 1}}dx\]
\[\text{Putting}\  3 x^2 - 5x + 1 = t\]
\[ \Rightarrow \left( 6x - 5 \right) dx = dt\]
\[\text{ Then }, \]
\[I = \int\frac{dt}{\sqrt{t}}\]
\[ = 2\sqrt{t} + C\]
\[ = 2\sqrt{3 x^2 - 5x + 1} + C\]

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अध्याय 19: Indefinite Integrals - Exercise 19.21 [पृष्ठ ११०]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.21 | Q 4 | पृष्ठ ११०

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