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RD Sharma solutions for Mathematics [English] Class 8 chapter 18 - Practical Geometry (Constructions) [Latest edition]

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RD Sharma solutions for Mathematics [English] Class 8 chapter 18 - Practical Geometry (Constructions) - Shaalaa.com
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Solutions for Chapter 18: Practical Geometry (Constructions)

Below listed, you can find solutions for Chapter 18 of CBSE RD Sharma for Mathematics [English] Class 8.


Exercise 18.1Exercise 18.2Exercise 18.3Exercise 18.4Exercise 18.5
Exercise 18.1 [Page 4]

RD Sharma solutions for Mathematics [English] Class 8 18 Practical Geometry (Constructions) Exercise 18.1 [Page 4]

1Page 4

Construct a quadrilateral ABCD in which AB = 4.4 cm, BC = 4 cm, CD = 6.4 cm, DA = 3.8 cm and BD= 6.6 cm.

2Page 4

Construct a quadrilateral ABCD such that AB = BC = 5.5 cm, CD = 4 cm, DA = 6.3 cm and AC = 9.4 cm. Measure BD.

3Page 4

Construct a quadrilateral XYZW in which XY = 5 cm, YZ = 6 cm, ZW = 7 cm, WX = 3 cm and XZ = 9 cm.

4Page 4

Construct a parallelogram PQRS such that PQ = 5.2 cm, PR = 6.8 cm and QS = 8.2 cm.

5Page 4

Construct a rhombus with side 6 cm and one diagonal 8 cm. Measure the other diagonal.

6Page 4

Construct a kite ABCD in which AB = 4 cm, BC = 4.9 cm and AC = 7.2 cm.

7Page 4

Construct, if possible, a quadrilateral ABCD given AB = 6 cm, BC = 3.7 cm, CD = 5.7 cm, AD = 5.5 cm and BD = 6.1 cm. Give reasons for not being able to construct it, if you cannot.

8Page 4

Construct, if possible, a quadrilateral ABCD in which AB = 6 cm, BC = 7 cm, CD = 3 cm, AD = 5.5 cm and AC = 11 cm. Give reasons for not being able to construct, if you cannot. (Not possible, because in triangle ACD, AD + CD < AC).

Exercise 18.2 [Page 6]

RD Sharma solutions for Mathematics [English] Class 8 18 Practical Geometry (Constructions) Exercise 18.2 [Page 6]

1Page 6

Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 3.8 cm.

2Page 6

Construct a quadrilateral ABCD in which BC = 7.5 cm, AC = AD = 6 cm, CD = 5 cm and BD = 10 cm.

3Page 6

Construct a quadrilateral ABCD, when AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 8 cm and BD = 4 cm.

4Page 6

Construct a quadrilateral ABCD given AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 cm, AC = 7.3 cm and BD = 3.2 cm.

5Page 6

Construct a quadrilateral ABCD given AD = 5 cm, AB = 5.5 cm, BC = 2.5 cm, AC = 7.1 cm and BD = 8 cm.

6Page 6

Construct a quadrilateral ABCD in which BC = 4 cm, CA = 5.6 cm, AD = 4.5 cm, CD = 5 cm and BD = 6.5 cm. 

Exercise 18.3 [Page 8]

RD Sharma solutions for Mathematics [English] Class 8 18 Practical Geometry (Constructions) Exercise 18.3 [Page 8]

1Page 8

Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ∠B= 80°.

2Page 8

Construct a quadrilateral ABCD, given that AB = 8 cm, BC = 8 cm, CD = 10 cm, AD = 10 cm and ∠A = 45°.

3Page 8

Construct a quadrilateral ABCD in which AB = 7.7 cm, BC = 6.8 cm, CD = 5.1 cm, AD = 3.6 cm and ∠C = 120°.

4Page 8

Construct a quadrilateral ABCD in which AB = BC = 3 cm, AD = CD = 5 cm, and ∠B = 120°.

5Page 8

Construct a quadrilateral ABCD in which AB = 2.8 cm, BC = 3.1 cm, CD = 2.6 cm, and DA = 3.3 cm and ∠A = 60°.

6Page 8

Construct a quadrilateral ABCD in which AB = BC = 6 cm, AD = DC = 4.5 cm and ∠B = 120°.

Exercise 18.4 [Pages 10 - 11]

RD Sharma solutions for Mathematics [English] Class 8 18 Practical Geometry (Constructions) Exercise 18.4 [Pages 10 - 11]

1Page 10

Construct a quadrilateral ABCD, in which AB = 6 cm, BC = 4 cm, CD = 4 cm, ∠B = 95° and ∠C = 90°.

2Page 10

Construct a quadrilateral ABCD, where AB = 4.2 cm, BC = 3.6 cm, CD = 4.8 cm, ∠B = 30° and ∠C = 150°.

3Page 10

Construct a quadrilateral PQRS, in which PQ = 3.5 cm, QR = 2.5 cm, RS = 4.1 cm, ∠Q = 75° and ∠R = 120°.

4Page 11

Construct a quadrilateral ABCD given BC = 6.6 cm, CD = 4.4 cm, AD = 5.6 cm and ∠D = 100° and ∠C= 95°.

5Page 11

Construct a quadrilateral ABCD, in which AD = 3.5 cm, AB = 4.4 cm, BC = 4.7 cm, ∠A = 125° and ∠B= 120°.

6Page 11

Construct a quadrilateral PQRS, in which ∠Q = 45°, ∠R = 90°, QR = 5 cm, PQ = 9 cm and Rs = 7 cm.

7Page 11

Construct a quadrilateral ABCD, in which AB = BC = 3 cm, AD = 5 cm, ∠A = 90° and ∠B = 105°.

8Page 11

Construct a quadrilateral BDEF, where DE = 4.5 cm, EF = 3.5 cm, FB = 6.5 cm, ∠F = 50° and ∠E = 100°.

Exercise 18.5 [Page 13]

RD Sharma solutions for Mathematics [English] Class 8 18 Practical Geometry (Constructions) Exercise 18.5 [Page 13]

1Page 13

Construct a quadrilateral ABCD given that AB = 4 cm, BC = 3 cm, ∠A = 75°, ∠B = 80° and ∠C = 120°.

2Page 13

Construct a quadrilateral ABCD, where AB = 5.5 cm, BC = 3.7 cm, ∠A = 60°, ∠B = 105° and ∠D = 90°.

3Page 13

Construct a quadrilateral PQRS, where PQ = 3.5 cm, QR = 6.5 cm, ∠P = ∠R = 105° and ∠S = 75°.

4Page 13

Construct a quadrilateral ABCD when BC = 5.5 cm, CD = 4.1 cm, ∠A = 70°, ∠B = 110° and ∠D = 85°.

5Page 13

Construct a quadrilateral ABCD, where ∠A = 65°, ∠B = 105°, ∠C = 75° BC = 5.7 cm and CD = 6.8 cm.

6Page 13

Construct a quadrilateral PQRS, in which PQ = 4 cm, QR = 5 cm, ∠P = 50°, ∠Q = 110° and ∠R = 70°.

Solutions for 18: Practical Geometry (Constructions)

Exercise 18.1Exercise 18.2Exercise 18.3Exercise 18.4Exercise 18.5
RD Sharma solutions for Mathematics [English] Class 8 chapter 18 - Practical Geometry (Constructions) - Shaalaa.com

RD Sharma solutions for Mathematics [English] Class 8 chapter 18 - Practical Geometry (Constructions)

Shaalaa.com has the CBSE Mathematics Mathematics [English] Class 8 CBSE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. RD Sharma solutions for Mathematics Mathematics [English] Class 8 CBSE 18 (Practical Geometry (Constructions)) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in Mathematics [English] Class 8 chapter 18 Practical Geometry (Constructions) are Constructing a Quadrilateral When the Lengths of Four Sides and a Diagonal Are Given, Constructing a Quadrilateral When Two Diagonals and Three Sides Are Given, Constructing a Quadrilateral When Two Adjacent Sides and Three Angles Are Known, Constructing a Quadrilateral When Three Sides and Two Included Angles Are Given, Some Special Cases, Geometric Tool.

Using RD Sharma Mathematics [English] Class 8 solutions Practical Geometry (Constructions) exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in RD Sharma Solutions are essential questions that can be asked in the final exam. Maximum CBSE Mathematics [English] Class 8 students prefer RD Sharma Textbook Solutions to score more in exams.

Get the free view of Chapter 18, Practical Geometry (Constructions) Mathematics [English] Class 8 additional questions for Mathematics Mathematics [English] Class 8 CBSE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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