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NCERT solutions for Mathematics [English] Class 6 chapter 14 - Practical Geometry [Latest edition]

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NCERT solutions for Mathematics [English] Class 6 chapter 14 - Practical Geometry - Shaalaa.com
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Solutions for Chapter 14: Practical Geometry

Below listed, you can find solutions for Chapter 14 of CBSE NCERT for Mathematics [English] Class 6.


Exercise 14.1Exercise 14.2Exercise 14.3Exercise 14.4Exercise 14.5Exercise 14.6
Exercise 14.1 [Page 276]

NCERT solutions for Mathematics [English] Class 6 14 Practical Geometry Exercise 14.1 [Page 276]

1.Page 276

Draw a circle of radius 3.2 cm.

2.Page 276

With the same centre O, draw two circles of radii 4 cm and 2.5 cm.

3.Page 276

Draw a circle and any two of its diameters. If you join the ends of these diameters, what is the figure obtained? What figure is obtained if the diameters are perpendicular to each other? How do you check your answer?

4.Page 276

Draw any circle and mark points A, B and C such that

  1. A is on the circle.
  2. B is in the interior of the circle.

  3. C is in the exterior of the circle.
5.Page 276

Let A, B be the centres of two circles of equal radii; draw them so that each one of them passes through the centre of the other. Let them intersect at C and D. Examine whether `overline("AB")` and `overline"CD"` are at right angles.

Exercise 14.2 [Page 278]

NCERT solutions for Mathematics [English] Class 6 14 Practical Geometry Exercise 14.2 [Page 278]

1.Page 278

Draw a line segment of length 7.3 cm using a ruler.

2.Page 278

Construct a line segment of length 5.6 cm using ruler and compasses.

3.Page 278

Construct `overline"AB"` of length 7.8 cm. From this, cut off `overline"AC"` of length 4.7 cm. Measure `overline"BC"`. 

4.Page 278

Given `overline"AB"` of length 3.9 cm, construct `overline"PQ"`  such that the length of `overline"PQ"` is twice that of `overline"AB"`. Verify by measurement.

(Hint: construct `overline"PX"` such that length of `overline"PX"` = length of  `overline"AB"`; then cut off  `overline"XQ"` such that `overline"XQ"` also has the length of `overline"AB"`.) 

5.Page 278

Given `overline"AB"` of length 7.3 cm and `overline"CD"` of length 3.4 cm, construct a line segment `overline"XY"` such that the length of `overline"XY"` is equal to the difference between the lengths of `overline"AB"` and `overline"CD"`. Verify by measurement.

Exercise 14.3 [Page 279]

NCERT solutions for Mathematics [English] Class 6 14 Practical Geometry Exercise 14.3 [Page 279]

1.Page 279

Draw any line segment `overline"PQ"`. Without measuring `overline"PQ"`, construct a copy of `overline"PQ"`.

2.Page 279

Given some line segment `overline"AB"`, whose length you do not know, construct `overline"PQ"` such that the length of `overline"PQ"` is twice that of `overline"AB"`. 

Exercise 14.4 [Page 284]

NCERT solutions for Mathematics [English] Class 6 14 Practical Geometry Exercise 14.4 [Page 284]

1.Page 284

Draw any line segment `overline"AB"`. Mark any point M on it. Through M, draw a perpendicular to `overline"AB"`. (use ruler and compasses)  

2.Page 284

Draw any line segment `overline"PQ"`. Take any point R not on it. Through R, draw a perpendicular to `overline"PQ"`. (use ruler and set-square)

3.Page 284

Draw a line l and point X on it. Through X, draw a line segment `overline"XY"` perpendicular to l.

Now draw a perpendicular `overline"XY"` to at Y. (use ruler and compasses) 

Exercise 14.5 [Page 286]

NCERT solutions for Mathematics [English] Class 6 14 Practical Geometry Exercise 14.5 [Page 286]

1.Page 286

Draw `overline"AB"` of length 7.3 cm and find its axis of symmetry.

2.Page 286

Draw a line segment of length 9.5 cm and construct its perpendicular bisector.

3.Page 286

Draw the perpendicular bisector of `overline"XY"` whose length is 10.3 cm.

  1. Take any point P on the bisector drawn. Examine whether PX = PY
  2. If M is the midpoint of `overline"XY"`, what can you say about the lengths MX and XY?

4.Page 286

Draw a line segment of length 12.8 cm. Using compasses, divide it into four equal parts. Verify by actual measurement.

5.Page 286

With `overline"PQ"` of length 6.1 cm as diameter, draw a circle.

6.Page 286

Draw a circle with centre C and radius 3.4 cm. Draw any chord `overline"AB"`. Construct the perpendicular bisector of `overline"AB"` and examine if it passes through C.

7.Page 286

Repeat Question 6, if `overline"AB"` happens to be a diameter.

8.Page 286

Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet?

9.Page 286

Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of `overline"OA"` and `overline"OB"`. Let them meet at P. Is PA = PB ?

Exercise 14.6 [Page 291]

NCERT solutions for Mathematics [English] Class 6 14 Practical Geometry Exercise 14.6 [Page 291]

1.Page 291

Draw ∠POQ of measure 75° and find its line of symmetry. 

2.Page 291

Draw an angle of measure 147° and construct its bisector.

3.Page 291

Draw a right angle and construct its bisector.

4.Page 291

Draw an angle of measure 153° and divide it into four equal parts.

5. (a)Page 291

Construct with ruler and compass, angle of 60° measure.

5. (b)Page 291

Construct with ruler and compass, angle of 30° measure.

5. (c)Page 291

Construct with ruler and compass, angle of 90° measure.

5. (d)Page 291

Construct with ruler and compass, angle of 120° measure.

5. (e)Page 291

Construct with ruler and compass, angle of 45° measure.

5. (f)Page 291

Construct with ruler and compass, angle of 135° measure.

6.Page 291

Draw an angle of measure 45° and bisect it.

7.Page 291

Draw an angle of measure 135° and bisect it.

8.Page 291

Draw an angle of 70°. Make a copy of it using only a straight edge and compasses.

9.Page 291

Draw an angle of 40°. Copy its supplementary angle.

Solutions for 14: Practical Geometry

Exercise 14.1Exercise 14.2Exercise 14.3Exercise 14.4Exercise 14.5Exercise 14.6
NCERT solutions for Mathematics [English] Class 6 chapter 14 - Practical Geometry - Shaalaa.com

NCERT solutions for Mathematics [English] Class 6 chapter 14 - Practical Geometry

Shaalaa.com has the CBSE Mathematics Mathematics [English] Class 6 CBSE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT solutions for Mathematics Mathematics [English] Class 6 CBSE 14 (Practical Geometry) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. NCERT textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics [English] Class 6 chapter 14 Practical Geometry are .

Using NCERT Mathematics [English] Class 6 solutions Practical Geometry exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in NCERT Solutions are essential questions that can be asked in the final exam. Maximum CBSE Mathematics [English] Class 6 students prefer NCERT Textbook Solutions to score more in exams.

Get the free view of Chapter 14, Practical Geometry Mathematics [English] Class 6 additional questions for Mathematics Mathematics [English] Class 6 CBSE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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