SSC (English Medium) 10th Standard - Maharashtra State Board Question Bank Solutions for Geometry Mathematics 2

Prove that:

Prove that:

(secθ - cosθ)(cotθ + tanθ) = tanθ.secθ.

Prove that:

Prove that: `1/"sec θ − tan θ" = "sec θ + tan θ"`

Prove that:

Prove that:
If \[\tan\theta + \frac{1}{\tan\theta} = 2\], then show that \[\tan^2 \theta + \frac{1}{\tan^2 \theta} = 2\]

Prove that:

Choose the correct alternative answer for the following question.
sin \[\theta\] cosec \[\theta\]= ?

Choose the correct alternative answer for the following question.
cosec 45^° =?

Choose the correct alternative answer for the following question.

1 + tan² \[\theta\]  = ?

Choose the correct alternative answer for the following question.

Prove the following.

secθ (1 – sinθ) (secθ + tanθ) = 1

Prove the following.
(secθ + tanθ) (1 – sinθ) = cosθ

Prove the following.
sec²θ + cosec²θ = sec²θ × cosec²θ 

Prove the following.
cot²θ – tan²θ = cosec²θ – sec²θ

Prove the following.

Prove the following:

sec⁶x – tan⁶x = 1 + 3sec²x × tan²x

Prove the following.

\[\frac{\tan\theta}{\sec\theta + 1} = \frac{\sec\theta - 1}{\tan\theta}\]

Prove the following.

Find the length of the hypotenuse in a right angled triangle where the sum
of the squares of the sides making right angle is 169.
(A)15 (B) 13 (C) 5 (D) 12