English
Karnataka Board PUCPUC Science Class 11

PUC Science Class 11 - Karnataka Board PUC Question Bank Solutions

Advertisements
[object Object]
[object Object]
Subjects
Popular subjects
Topics

Please select a subject first

Advertisements
Advertisements
< prev  1181 to 1200 of 4962  next > 

Which term of the G.P. :

\[2, 2\sqrt{2}, 4, . . .\text {  is }128 ?\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Which term of the G.P.: `sqrt3, 3, 3sqrt3`, ... is 729?

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Advertisements

Which term of the G.P. :

\[\frac{1}{3}, \frac{1}{9}, \frac{1}{27} . . \text { . is } \frac{1}{19683} ?\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Prove that:
\[\frac{\tan \left( A + B \right)}{\cot \left( A - B \right)} = \frac{\tan^2 A - \tan^2 B}{1 - \tan^2 A \tan^2 B}\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Which term of the progression 18, −12, 8, ... is \[\frac{512}{729}\] ?

 
[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Prove that:
tan 8x − tan 6x − tan 2x = tan 8x tan 6x tan 2x

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
\[\tan\frac{\pi}{12} + \tan\frac{\pi}{6} + \tan\frac{\pi}{12}\tan\frac{\pi}{6} = 1\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
tan 36° + tan 9° + tan 36° tan 9° = 1

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove that:
tan 13x − tan 9x − tan 4x = tan 13x tan 9x tan 4x

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Find the 4th term from the end of the G.P.

\[\frac{1}{2}, \frac{1}{6}, \frac{1}{18}, \frac{1}{54}, . . . , \frac{1}{4374}\]

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

The fourth term of a G.P. is 27 and the 7th term is 729, find the G.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Prove that:
\[\frac{\tan^2 2x - \tan^2 x}{1 - \tan^2 2x \tan^2 x} = \tan 3x \tan x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

The seventh term of a G.P. is 8 times the fourth term and 5th term is 48. Find the G.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Prove that sin2 (n + 1) A − sin2 nA = sin (2n + 1) A sin A.

 
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If the G.P.'s 5, 10, 20, ... and 1280, 640, 320, ... have their nth terms equal, find the value of n.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If tan A = x tan B, prove that
\[\frac{\sin \left( A - B \right)}{\sin \left( A + B \right)} = \frac{x - 1}{x + 1}\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If tan (A + B) = x and tan (A − B) = y, find the values of tan 2A and tan 2B.

 
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If 5th, 8th and 11th terms of a G.P. are p. q and s respectively, prove that q2 = ps.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If cos A + sin B = m and sin A + cos B = n, prove that 2 sin (A + B) = m2 + n2 − 2.

 
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If tan A + tan B = a and cot A + cot B = b, prove that cot (A + B) \[\frac{1}{a} - \frac{1}{b}\].

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined
< prev  1181 to 1200 of 4962  next > 
Advertisements
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×