English
Karnataka Board PUCPUC Science Class 11

PUC Science Class 11 - Karnataka Board PUC Question Bank Solutions for Mathematics

Advertisements
[object Object]
[object Object]
Subjects
Popular subjects
Topics
Advertisements
Advertisements
Mathematics
< prev  2901 to 2920 of 3275  next > 

A point moves so that the difference of its distances from (ae, 0) and (−ae, 0) is 2a. Prove that the equation to its locus is \[\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\]

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find the locus of a point such that the sum of its distances from (0, 2) and (0, −2) is 6.

 
[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Advertisements

Find the locus of a point which is equidistant from (1, 3) and the x-axis.

 
[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find the locus of a point which moves such that its distance from the origin is three times its distance from the x-axis.

 
[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

A (5, 3), B (3, −2) are two fixed points; find the equation to the locus of a point P which moves so that the area of the triangle PAB is 9 units.

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find the locus of a point such that the line segments with end points (2, 0) and (−2, 0) subtend a right angle at that point.

 
[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

If A (−1, 1) and B (2, 3) are two fixed points, find the locus of a point P, so that the area of ∆PAB = 8 sq. units.

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

A rod of length l slides between two perpendicular lines. Find the locus of the point on the rod which divides it in the ratio 1 : 2.

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find the locus of the mid-point of the portion of the line x cos α + y sin α = p which is intercepted between the axes.

 
[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

If O is the origin and Q is a variable point on y2 = x, find the locus of the mid-point of OQ.

 
[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

What does the equation (x − a)2 + (y − b)2 = r2 become when the axes are transferred to parallel axes through the point (a − c, b)?

 
[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

What does the equation (a − b) (x2 + y2) −2abx = 0 become if the origin is shifted to the point \[\left( \frac{ab}{a - b}, 0 \right)\] without rotation?

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find what the following equation become when the origin is shifted to the point (1, 1).
x2 + xy − 3x − y + 2 = 0

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find what the following equation become when the origin is shifted to the point (1, 1).
 x2 − y2 − 2x +2y = 0

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find what the following equation become when the origin is shifted to the point (1, 1).
xy − x − y + 1 = 0

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find what the following equation become when the origin is shifted to the point (1, 1).
xy − y2 − x + y = 0

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

To what point should the origin be shifted so that the equation x2 + xy − 3x − y + 2 = 0 does not contain any first degree term and constant term?

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Verify that the area of the triangle with vertices (2, 3), (5, 7) and (− 3 − 1) remains invariant under the translation of axes when the origin is shifted to the point (−1, 3).

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find what the following equation become when the origin is shifted to the point (1, 1).
x2 + xy − 3y2 − y + 2 = 0

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Find what the following equation become when the origin is shifted to the point (1, 1).
xy − y2 − x + y = 0

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined
< prev  2901 to 2920 of 3275  next > 
Advertisements
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×