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Commerce (English Medium) Class 12 - CBSE Question Bank Solutions for Mathematics

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F(x, y) = `(ycos(y/x) + x)/(xcos(y/x))` is not a homogeneous function.

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

F(x, y) = `(x^2 + y^2)/(x - y)` is a homogeneous function of degree 1.

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

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Solve : `x^2 "dy"/"dx"` = x2 + xy + y2.

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solcve: `x ("d"y)/("d"x) = y(log y – log x + 1)`

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

If A `= [(1,2),(2,1)]` and f(x) = (1 + x) (1 - x), then f(a) is ____________.

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

If A `= [(2"x", 0),("x","x")] "and A"^-1 = [(1,0),(-1,2)],` then x equals ____________.

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

If | A | = | kA |, where A is a square matrix of order 2, then sum of all possible values of k is ______.

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

Find the general solution of the differential equation:

(xy – x2) dy = y2 dx

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Read the following passage:

An equation involving derivatives of the dependent variable with respect to the independent variables is called a differential equation. A differential equation of the form `dy/dx` = F(x, y) is said to be homogeneous if F(x, y) is a homogeneous function of degree zero, whereas a function F(x, y) is a homogeneous function of degree n if F(λx, λy) = λn F(x, y).

To solve a homogeneous differential equation of the type `dy/dx` = F(x, y) = `g(y/x)`, we make the substitution y = vx and then separate the variables.

Based on the above, answer the following questions:

  1. Show that (x2 – y2) dx + 2xy dy = 0 is a differential equation of the type `dy/dx = g(y/x)`. (2)
  2. Solve the above equation to find its general solution. (2)
[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Write the number of vectors of unit length perpendicular to both the vectors `veca=2hati+hatj+2hatk and vecb=hatj+hatk`

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Find : `int x^2/(x^4+x^2-2) dx`

[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined

If `veca=4hati-hatj+hatk` then find a unit vector parallel to the vector `veca+vecb`

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

If the function f : R → R be defined by f(x) = 2x − 3 and g : R → R by g(x) = x3 + 5, then find the value of (fog)−1 (x).

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Evaluate:

`int x^2/(x^4+x^2-2)dx`

[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined

Let f : W → W be defined as

`f(n)={(n-1, " if n is odd"),(n+1, "if n is even") :}`

Show that f is invertible a nd find the inverse of f. Here, W is the set of all whole
numbers.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find: `I=intdx/(sinx+sin2x)`

[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined

Let f: {1, 3, 4} → {1, 2, 5} and g: {1, 2, 5} → {1, 3} be given by f = {(1, 2), (3, 5), (4, 1)} and g = {(1, 3), (2, 3), (5, 1)}. Write down gof.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let f, g and h be functions from R to R. Show that

(f + g)oh = foh + goh

(f · g)oh = (foh)·(goh)

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find gof and fog, if f(x) = |x| and g(x) = |5x – 2|.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find gof and fog, if f(x) = 8x3 and `g(x) = x^(1/3)`.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined
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