Definitions [10]
A differential equation that contains ordinary derivatives of one or more dependent variables with respect to a single independent variable is called an ordinary differential equation.
Example:
If an equation contains derivatives of one dependent variable with respect to one or more independent variables, then it is called a differential equation.
Example
This is a differential equation because it contains the derivative \[\frac{dy}{dx}\].
The highest exponent of the highest derivative is called the degree of a differential equation, provided exponents of each derivative and an unknown variable appearing in the differential equation are non-negative integers.
The order of the highest differential coefficient (or the highest order derivative appearing in a differential equation) is the order of the differential equation.
The equation \[\frac{dy}{dx} = F(x, y)\] is said to be in variable separable form if it can be expressed as \[g(x) dx = h(y) dy\] or equivalently as \[\frac{dy}{dx} = g(x)h(y)\] so that the variables can be separated and integrated.
A differential equation of the form \[\frac{dy}{dx}=\frac{f_{1}(x,y)}{f_{2}(x,y)},\] where f1(x, y) ) and f2(x, y) are homogeneous functions of x and y of the same degree, is called a homogeneous differential equation.
A linear differential equation of first order and first degree is
\[\frac{\mathrm{d}y}{\mathrm{d}x}+\mathrm{P}y=\mathrm{Q}\], where P and Q are the functions of x or constants. Its general solution is \[y.\left(\mathrm{I.F.}\right)=\int\mathrm{Q.}\left(\mathrm{I.F.}\right)\mathrm{d}x+\mathrm{c}\] and the function \[\mathrm{e}^{\int\mathrm{Pdx}}\] is called the integrating factor (I.F.) of the given equation.
The factor e∫P dx on multiplying by which the left-hand side of the differential equation\[\frac{dy}{dx}+Py=Q\] becomes the differential coefficient of a function of x and y, is called the integrating factor of the differential equation.
General Solution: \[y\cdot\mathrm{I.F.}=\int Q\cdot\mathrm{I.F.}dx+c\]
A differential equation is non-linear if any one of the following holds:
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The degree is more than one
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Any differential coefficient has an exponent of more than one
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Exponent of the dependent variable is more than one
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Products containing the dependent variable and its differential coefficients are present
A first-order differential equation, along with an initial condition, is called an initial value problem.
Theorems and Laws [1]
Prove that:
`int_0^(2a)f(x)dx = int_0^af(x)dx + int_0^af(2a - x)dx`
Since ‘a’ lies between 0 and 2a,
we have
`int_0^(2a)f(x)dx=int_0^af(x)dx+int_a^(2a)f(x)dx, .......(byint_a^bf(x)dx=int_a^cf(x)dx+int_c^bf(x)dx)`
`=I_1+I_2` ........................(say)
`I_2 = int_a^(2a)f(x)dx`
Put x = 2a − t
Therefore, dx = −dt
When x = a, 2a − t = a
t = a
When x = 2a, 2a − t = 2a
t = 0
`I_2 = int_0^(2a) f(x) dx = int_a^0 f(2a - t) (-dt)`
`= -int_a^0 f(2a - t)dt = int_0^a f(2a - t)dt ...................... (By int_a^b f(x)dx = -int_b^a f(x)dx)`
`=int_0^a f(2a - x)dx ..............(By int_a^b f(X)dx = int_a^b f(t)dt)`
`int_0^(2a) f(x)dx = int_0^a f(x)dx + int_0^a f(2a - x)dx`
`= int_0^a [f(x) + f(2a - x)]dx`
To show that:
`int_0^pi sin x dx = 2 int_0^(pi/2) sin x dx`
We use the proven property by setting f(x) = sin x and 2a = π, which means a = `pi/2`.
The property tells us that:
`int_0^pi sin x dx = int_0^(pi/2) sin x dx + int_0^(pi/2) sin (pi - x) dx`
Knowing the trigonometric identity sin (π - x) = sin x, the equation simplifies to:
`int_0^pi sin x dx = 2 int_0^(pi/2) sin x dx`
This directly applies the property to the integral of sin x over [0, π] to show it equals twice the integral of sin x over `[0, pi/2]`, demonstrating the utility of this property in simplifying integrals with symmetric functions over specific intervals.
Key Points
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A differential equation contains derivatives.
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An ordinary differential equation contains derivatives with respect to only one independent variable.
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Differential equations describe rates of change in mathematics and science.
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Order = highest derivative order.
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Degree = power of highest derivative.
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Degree exists only for polynomial equations in derivatives.
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Always check polynomial condition before stating the degree.
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Variable separable equations can be rewritten as x-part = y-part.
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Separate variables first, then integrate.
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Use one constant of integration.
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Apply the initial condition only after getting the general solution.
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Final answers may be explicit or implicit.
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Check homogeneity first.
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Differentiate substitution carefully.
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Convert to separable form.
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Back-substitute to original variables.
- Write the equation in the form dy/dx + Py = Q
- Identify P and Q
- Find I.F. = \[\mathrm{e}^{\int\mathrm{Pdx}}\]
- Multiply the whole equation by I.F.
- Integrate and get a solution.
1. Population Growth
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Rate of change of population ∝ population
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\[\frac{\mathrm{dP}}{\mathrm{dt}}=\mathrm{kP}\]
Growth increases with time
2. Radioactive Decay
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Rate of decay ∝ of the amount present
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\[\frac{\mathrm{d}x}{\mathrm{d}t}=-\mathrm{k}x\]
Negative sign → quantity decreases
3. Newton’s Law of Cooling
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Rate of cooling ∝ temperature difference
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\[\frac{\mathrm{d}\theta}{\mathrm{d}t}=-k\left(\theta-\theta_{0}\right)\]
θ = body temp, θ₀ = surrounding temp
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Write the equation in the form
\[\frac{dy}{dx}+Py=Q\] -
Find the integrating factor
\[\mathrm{I.F.}=e^{\int Pdx}\] -
Multiply the entire equation by I.F.
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Integrate both sides w.r.t x
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Obtain
\[y(\mathrm{I.F.})=\int Q(\mathrm{I.F.})dx+c\]
- Radioactive Decay: \[x=x_0e^{-kt}\]
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Half-Life Formula: \[k=\frac{\ln2}{T}\]
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Newton’s Law of Cooling: \[\theta=\theta_0+(\theta_1-\theta_0)e^{-kt}\]
- Population Growth: \[P=ae^{kt}\]
Important Questions [12]
- For the differential equation, find the particular solution (x – y2x) dx – (y + x2y) dy = 0 when x = 2, y = 0
- The differential equation of y=k1ex+k2e-x is ______.
- The solution of 𝑑𝑦𝑑𝑥 = 1 is ______.
- Find the differential equation whose general solution is x3 + y3 = 35ax.
- A solution of a differential equation which can be obtained from the general solution by giving particular values to the arbitrary constants is called ___________ solution.
- The integrating factor of the differential equation dydx-y=x is e−x.
- Solve the following differential equation. x2y dx − (x3 + y3) dy = 0
- The degree of the differential equation (d2ydx2)2+(dydx)3 = ax is 3.
- State whether the following statement is true or false: Order and degree of a differential equation are always positive integers.
- The order and degree of the differential equation [1+(dydx)3]23=8(d3ydx3) are respectively ______.
- Y2 = (x + c)3 is the general solution of the differential equation ______.
- Obtain the differential equation by eliminating arbitrary constants from the following equation: y = Ae3x + Be–3x
Concepts [8]
- Basic Concepts of Differential Equations
- Order and Degree of a Differential Equation
- Formation of Differential Equation by Eliminating Arbitary Constant
- Methods of Solving Differential Equations> Variable Separable Differential Equations
- Methods of Solving Differential Equations> Homogeneous Differential Equations
- Methods of Solving Differential Equations>Linear Differential Equations
- Applications of Differential Equation
- Overview of Differential Equations
