Advertisements
Advertisements
Question
x3 − 10x2 − 53x − 42
Advertisements
Solution
Let `f(x) = x^3 - 10x^2 - 53x -42` be the given polynomial.
Now, putting x = -1 we get
`f(-1) = (-1)^3 - 10(-1)^2 - 53(-1) - 42`
` = -1-10 + 53 - 42`
` = -53 + 53 = 0`
Therefore, (x + 1)is a factor of polynomial f(x).
Now,
`f(x) = x^2 (x+1) -11x(x+1) - 42(x+1)`
` = (x+1){x^2 -11x - 42}`
` = (x + 1){x^2 - 14x + 3x - 42}`
` = (x +1)(x+3)(x - 14)`
Hence (x+1),(x + 3) and (x - 14)are the factors of polynomial f(x).
APPEARS IN
RELATED QUESTIONS
Write the degrees of the following polynomials:
7
If f(x) = 2x2 - 13x2 + 17x + 12 find f(-3).
The polynomials ax3 + 3x2 − 3 and 2x3 − 5x + a when divided by (x − 4) leave the remainders R1 and R2 respectively. Find the value of the following case, if R1 = R2.
The polynomials ax3 + 3x2 − 3 and 2x3 − 5x + a when divided by (x − 4) leave the remainders R1 and R2 respectively. Find the values of the following cases, if 2R1 − R2 = 0.
Find the value of a such that (x − 4) is a factors of 5x3 − 7x2 − ax − 28.
x3 − 6x2 + 3x + 10
Factorize of the following polynomials:
4x3 + 20x2 + 33x + 18 given that 2x + 3 is a factor.
If x − a is a factor of x3 −3x2a + 2a2x + b, then the value of b is
If x − 3 is a factor of x2 − ax − 15, then a =
Let f(x) be a polynomial such that \[f\left( - \frac{1}{2} \right)\] = 0, then a factor of f(x) is
