Advertisements
Advertisements
Question
If x140 + 2x151 + k is divisible by x + 1, then the value of k is
Options
1
-3
2
-2
Advertisements
Solution
As f(x) = x140 + 2x151 + k is divisible by (x +1).
i.e., (x+1)is a factor of f(x).
Therefore, f(-1) = 0
`(-1)^140+2(-1)^151 + k =0`
`1 -2 +k =0`
`k=1`
APPEARS IN
RELATED QUESTIONS
Identify polynomials in the following:
`p(x)=2/3x^3-7/4x+9`
If the polynomials 2x3 + ax2 + 3x − 5 and x3 + x2 − 4x +a leave the same remainder when divided by x −2, find the value of a.
The polynomials ax3 + 3x2 − 3 and 2x3 − 5x + a when divided by (x − 4) leave the remainders R1 and R2 respectively. Find the values of the following cases, if 2R1 − R2 = 0.
f(x) = 3x4 + 17x3 + 9x2 − 7x − 10; g(x) = x + 5
f(x) = 3x3 + x2 − 20x +12, g(x) = 3x − 2
What must be subtracted from x3 − 6x2 − 15x + 80 so that the result is exactly divisible by x2 + x − 12?
x3 − 3x2 − 9x − 5
One factor of x4 + x2 − 20 is x2 + 5. The other factor is
Factorise the following:
a2 + 10a – 600
Factorise the following:
`sqrt(5)"a"^2 + 2"a" - 3sqrt(5)`
