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Question
Write the negation of p → q
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Solution
∼ p → q ≡ (∼p ∨ q) .......[∵ p → q ≡ ∼p ∨ q]
≡ ∼ (∼p) ∨ ∼ q .......[De’Morgan’s Law]
≡ ∼ ∼ p ∧ ∼ q
≡ p ∧ ∼ q
≡ p ∧ (∼q)
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