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Question
Construct the truth table of the following:
(∼p ∨ ∼q) ↔ [∼(p ∧ q)]
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Solution
| p | q | ∼p | ∼q | ∼p ∨ ∼q | p∧q | ∼ (p∧q) | (∼p ∨ ∼q) ↔ [∼ (p∧q)] |
| T | T | F | F | F | T | F | T |
| T | F | F | T | T | F | T | T |
| F | T | T | F | T | F | T | T |
| F | F | T | T | T | F | T | T |
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