Advertisements
Advertisements
Question
Write six distinct integers whose sum is 7.
Advertisements
Solution
Let the six distinct integers be 1, 2, –2, 3, –3 and 6.
Now, sum of the above six distinct integers = 1 + 2 + (–2) + 3 + (–3) + 6
We can arrange the numbers, so that the positive integers and negative integers are grouped together.
We have, 1 + 2 + 3 + 6 + (–2) + (–3)
= 12 – 2 – 3
= 12 – 5
= 7
Hence, the required integers are 1, 2, –2, 3, –3 and 6.
Notes
There are infinite combinations exist.
APPEARS IN
RELATED QUESTIONS
State, true or false of the given statement:
product of two integers can be zero.
Add: 5 + (–6)
Add: –5 + ( –2)
For the following statement write (T) for true and (F) for false:
| −5| < |−3|
For the following statement write (T) for true and (F) for false:
|8 − 5| = |8| + |−5|
Subtract: 219 from 0
Multiply: (–746) by (–8)
8 + (−8) = ?
In the pair given below, find the larger integer.
An atom consists of charged particles called electrons and protons. Each proton has a charge of +1 and each electron has a charge of –1. Remember number of electrons is equal to number of protons, while answering these questions:
- What is the charge on an atom?
- What will be the charge on an atom if it loses an electron?
- What will be the charge on an atom if it gains an electron?
