Question

Write oxidation state of ‘Fe’ in \[\ce{[Fe(CN)6]^{4\ominus}}\] complex ion.

Answer 1

Charge number of complex ion = Oxidation state of metal ion + Charge of ligands

∴ Oxidation state of Fe ion + 6 × ( −1)

∴ Oxidation state of iron = − 4 + 6 

= +2