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प्रश्न
Write oxidation state of ‘Fe’ in \[\ce{[Fe(CN)6]^{4\ominus}}\] complex ion.
संख्यात्मक
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उत्तर
Charge number of complex ion = Oxidation state of metal ion + Charge of ligands
∴ Oxidation state of Fe ion + 6 × ( −1)
∴ Oxidation state of iron = − 4 + 6
= +2
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