Question

Write 6.0 g of O₂ reacts with ClF as per

\[\ce{2ClF_{(g)} + O2_{(g)} -> Cl2O_{(g)} + OF2_{(g)}}\]

The enthalpy change is 38.55 kJ. Calculate the standard enthalpy of the reaction.

Answer 1

\[\ce{2ClF_{(g)} + O2_{(g)} -> Cl2O_{(g)} + OF2_{(g)}}\]

For 6 g of oxygen,

ΔH = 38.55 kJ

for 32 g of oxygen,

ΔH = `(38.55 xx 32)/6`

= 205.6 kJ