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Question
Write the molecular formula of the 2nd and 3rd member of the homologous series whose first member is ethene.
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Solution
The general formula for the homologous series whose first member is ethene is CnH2n.
The two consecutive members (2nd and 3rd) of this series are:
a. CH3CH=CH2 (Propene); where n is 3
b. CH3CH2CH=CH2(1-Butene) or CH3CH=CHCH3 (2-Butene); where n is 4
The molecular formulae are C3H6 and C4H8 respectively.
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