Advertisements
Advertisements
Question
Write the molecular formula of the 2nd and 3rd member of the homologous series where the first member is ethyne.
Advertisements
Solution
The general formula for the homologous series whose first member is ethyne is CnH2n - 2.
The two consecutive members (2nd and 3rd) of this series are:
a. CH3C≡CH (Propyne); where n is 3
b. CH3CH2C≡CH(1-Butyne) or CH3C≡CCH3 (2-Butyne); where n is 4
The molecular formulae are C3H4 and C4H6, respectively.
APPEARS IN
RELATED QUESTIONS
Define a homologous series. Give the name and structural formula of one homologue of the following:
CH3OH
The molecular formula of an organic compound is C18H36. Name its homologous series.
Why homologous series of carbon compounds are so called? Write chemical formula of two consecutive members of a homologous series and state the part of these compounds that determines their (i) physical properties, and (ii) chemical properties.
Write names of first four homologous series of alcohols.
Write the name and formula of the fourth member of the following homologous series:
Alkyne
Find the odd one out and give its explanation.
As one ascends in any homologous series, physical properties change gradually.
Write a short note.
Homologous series
C3H8 belongs to the homologous series of ______.
Name the following organic compound:
The first homologue whose general formula is CnH2n.
