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प्रश्न
Write the molecular formula of the 2nd and 3rd member of the homologous series where the first member is ethyne.
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उत्तर
The general formula for the homologous series whose first member is ethyne is CnH2n - 2.
The two consecutive members (2nd and 3rd) of this series are:
a. CH3C≡CH (Propyne); where n is 3
b. CH3CH2C≡CH(1-Butyne) or CH3C≡CCH3 (2-Butyne); where n is 4
The molecular formulae are C3H4 and C4H6, respectively.
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संबंधित प्रश्न
Write the molecular formula of first two members of homologous series having functional group -Cl.
What is the next higher homologue of methanol (CH3OH)?
Define a homologous series. Give the name and structural formula of one homologue of the following:
CH3OH
Give the names and the structural formula of the first three members of the homologous series of alkanes.
Write the name and molecular formula of the first member of the homologous series of alkynes.
Write names of first four homologous series of alcohols.
Complete the following table for homologous series of alcohols.
| Name | Molecular formula | Condensed structural formula | Number of carbon atom | Number of -CH2- units | Boiling point °C |
| Methanol | CH4O | CH3-OH | 1 | 1 | 63 |
| Ethanol | C2H6O | CH3–CH2-OH | 2 | 2 | 78 |
| Propanol | C3H8O | CH3–CH2–CH2-OH | ______ | ______ | 97 |
| Butanol | C4H10O | CH3–CH2–CH2–CH2–OH | ______ | ______ | 118 |
Name the following organic compound:
The first homologue whose general formula is CnH2n.
Name the following:
Group of organic compounds where the successive members follow a regular structural pattern, successive compounds differ by a 'CH2' group.
