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प्रश्न
Write the molecular formula of the 2nd and 3rd member of the homologous series where the first member is ethyne.
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उत्तर
The general formula for the homologous series whose first member is ethyne is CnH2n - 2.
The two consecutive members (2nd and 3rd) of this series are:
a. CH3C≡CH (Propyne); where n is 3
b. CH3CH2C≡CH(1-Butyne) or CH3C≡CCH3 (2-Butyne); where n is 4
The molecular formulae are C3H4 and C4H6, respectively.
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संबंधित प्रश्न
Give the molecular formula of one homologue of the following:
C3H6
What is a homologous series? Explain with an example.
Give the names of the first four members of the homologous series of
alkynes.
Cyclohexane : Cyclic hydrocarbon : : Isobutylene : _______
Saturated hydrocarbon : Single bond : : Unsaturated hydrocarbon : _______
As one ascends in any homologous series, physical properties change gradually.
There are different general molecular formula for all members of the homologous series.
The first member of alkyne homologous series is
Consider the following molecular formulae of carbon compounds:
(i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H8
- Which one of these compounds belongs to homologous series of alcohols?
- Identify the compound having triple bond between carbon-carbon atoms.
- Write the molecular formula of the first member of the homologous series to which CH3COOH belongs.
- Write the general formula of the series to which the compound C4H8 belongs.
