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Write down the decimal expansions of the following rational numbers by writing their denominators in the form 2^m × 5^n, where m, n are non-negative integers. [\frac{129}{2^2 \times 5^7}]

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Question

Write down the decimal expansions of the following rational numbers by writing their denominators in the form 2m × 5n, where m, n are non-negative integers.

\[\frac{129}{2^2 \times 5^7}\]

Numerical
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Solution

The given number is \[\frac{129}{2^2 \times 5^7}\]. 

Clearly, 22 × 5is of the form 2m × 5n, where m = 2 and n = 7.

So, the given number has terminating decimal expansion.

\[\therefore \frac{129}{2^2 \times 5^7} = \frac{129 \times 2^5}{2^2 \times 5^7 \times 2^5} = \frac{129 \times 32}{\left( 2 \times 5 \right)^7} = \frac{4182}{\left( 10 \right)^7} = \frac{4182}{10000000} = 0 . 0004182\]

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Chapter 1: Real Numbers - EXERCISE 1.6 [Page 1.42]

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R.D. Sharma Mathematics [English] Class 10
Chapter 1 Real Numbers
EXERCISE 1.6 | Q 2. (v) | Page 1.42
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