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Question
Write an A.P. whose first term is a and common difference is d in the following.
a = 6, d = –3
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Solution
a = 6, d = –3
t1 = a = 6 ...[Given]
t2 = t1 + d = 6 + (-3) = 6 - 3 = 3
t3 = t2 + d = 3 + (-3) = 3 - 3 = 0
t4 = t3 + d = 0 + (-3) = 0 - 3 = -3
∴ The required A.P. is 6, 3, 0, -3, ...
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