Advertisements
Advertisements
Question
Write an A.P. whose first term is a and common difference is d in the following.
a = –19, d = –4
Advertisements
Solution
a = –19, d = –4
t1 = a = –19
t2 = a + d = –19 + (–4) = –19 – 4 = –23
t3 = a + 2d = –19 + 2(–4) = –19 – 8 = –27
t4 = a + 3d = –19 + 3(–4) = –19 – 12 = –31
∴ A.P. is –19, –23, –27, –31, .......
APPEARS IN
RELATED QUESTIONS
In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato and other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line.
A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?
[Hint: to pick up the first potato and the second potato, the total distance (in metres) run by a competitor is 2 × 5 + 2 ×(5 + 3)]
Find the sum 25 + 28 + 31 + ….. + 100
In an A.P. the first term is 25, nth term is –17 and the sum of n terms is 132. Find n and the common difference.
The first three terms of an AP are respectively (3y – 1), (3y + 5) and (5y + 1), find the value of y .
What is the sum of first n terms of the AP a, 3a, 5a, …..
Find the sum of the following Aps:
9, 7, 5, 3 … to 14 terms
If first term of an A.P. is a, second term is b and last term is c, then show that sum of all terms is \[\frac{\left( a + c \right) \left( b + c - 2a \right)}{2\left( b - a \right)}\].
If the sum of a certain number of terms starting from first term of an A.P. is 25, 22, 19, ..., is 116. Find the last term.
If in an A.P. Sn = n2p and Sm = m2p, where Sr denotes the sum of r terms of the A.P., then Sp is equal to
If Sn denote the sum of n terms of an A.P. with first term a and common difference dsuch that \[\frac{Sx}{Skx}\] is independent of x, then
The given terms are 2k + 1, 3k + 3 and 5k − 1. find AP.
Q.1
The sum of first 16 terms of the AP: 10, 6, 2,... is ______.
The middle most term(s) of the AP: -11, -7, -3,.... 49 is ______.
The first term of an AP of consecutive integers is p2 + 1. The sum of 2p + 1 terms of this AP is ______.
The sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms.
Find the sum of those integers from 1 to 500 which are multiples of 2 or 5.
[Hint (iii) : These numbers will be : multiples of 2 + multiples of 5 – multiples of 2 as well as of 5]
In an AP, if Sn = n(4n + 1), find the AP.
Find the sum of those integers from 1 to 500 which are multiples of 2 as well as of 5.
Measures of angles of a triangle are in A.P. The measure of smallest angle is five times of common difference. Find the measures of all angles of a triangle. (Assume the measures of angles as a, a + d, a + 2d)
