Advertisements
Advertisements
Question
Write a Pythagorean triplet whose one member is 14.
Advertisements
Solution
The three numbers of the Pythagorean triplet are 2m, m2 - 1, and m2 + 1.
Here, 2m = 14
so, m = 7
Second number (m2 - 1) = (7)2 - 1
= 49 - 1
= 48
Third number (m2 + 1) = (7)2 + 1
= 49 + 1
= 50
Hence the Pythagorean triplet is (14, 48, 50).
RELATED QUESTIONS
Write a Pythagorean triplet whose one member is 16.
What will be the units digit of the square of the following number?
12796
Observe the following pattern
22 − 12 = 2 + 1
32 − 22 = 3 + 2
42 − 32 = 4 + 3
52 − 42 = 5 + 4
and find the value of
1002 − 992
Observe the following pattern
\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) = \frac{2 \times 3 \times 4}{3}\]
\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) = \frac{3 \times 4 \times 5}{3}\]
\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) + \left( 4 \times 5 \right) = \frac{4 \times 5 \times 6}{3}\]
and find the value of(1 × 2) + (2 × 3) + (3 × 4) + (4 × 5) + (5 × 6)
Which of the following number square of even number?
1296
Which of the following number are square of even number?
6561
Find the squares of the following numbers using diagonal method:
273
Find the squares of the following numbers using diagonal method:
171
If m is the square of a natural number n, then n is ______.
