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Question
Write a Pythagorean triplet whose one member is 14.
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Solution
The three numbers of the Pythagorean triplet are 2m, m2 - 1, and m2 + 1.
Here, 2m = 14
so, m = 7
Second number (m2 - 1) = (7)2 - 1
= 49 - 1
= 48
Third number (m2 + 1) = (7)2 + 1
= 49 + 1
= 50
Hence the Pythagorean triplet is (14, 48, 50).
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