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Question
A 5.5 m long ladder is leaned against a wall. The ladder reaches the wall to a height of 4.4 m. Find the distance between the wall and the foot of the ladder.
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Solution
Let the distance between the wall and the foot of the ladder be x m
In right-angled ΔABC, by using Pythagoras theorem, we get
BC2 = AB2 + AC2
⇒ (5.5)2 = x2 + (4.4)2
⇒ x2 = (5.5)2 – (4.4)2
⇒ x2 = 30.25 – 19.36
⇒ x2 = 10.89
⇒ x = `sqrt(10.89)`
| 3.3 | |
| 3 | `bar10.bar89` |
| 9 | |
| 63 | 189 |
| 189 | |
| 0 |
∴ x = 3.3 m
Hence, the distance between the wall and the foot of the ladder is 3.3 m.
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