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Question
Rahul walks 12 m north from his house and turns west to walk 35 m to reach his friend’s house. While returning, he walks diagonally from his friend’s house to reach back to his house. What distance did he walk while returning?
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Solution
Let Rahul walked x m, while returning home.
In ΔABC, by using Pythagoras theorem, we get
AC2 = AB2 + BC2
⇒ AC2 = (12)2 + (35)2
⇒ AC2 = 144 + 1225 = 1369
⇒ AC = `sqrt(1369)`
⇒ AC = 37 m
| 37 | |
| 3 | `bar13` `bar69` |
| 9 | |
| 67 | 469 |
| 469 | |
| 0 |
Hence, Rahul walked 37 m distance for returning to his house diagonally.
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