Question

Rahul walks 12 m north from his house and turns west to walk 35 m to reach his friend’s house. While returning, he walks diagonally from his friend’s house to reach back to his house. What distance did he walk while returning?

Answer 1

Let Rahul walked x m, while returning home.

In ΔABC, by using Pythagoras theorem, we get

AC² = AB² + BC²

⇒ AC² = (12)² + (35)²

⇒ AC² = 144 + 1225 = 1369

⇒ AC = `sqrt(1369)`

⇒ AC = 37 m

	37
3	`bar13` `bar69`
	9
67	469
	469
	0

Hence, Rahul walked 37 m distance for returning to his house diagonally.