Advertisements
Advertisements
Question
Rahul walks 12 m north from his house and turns west to walk 35 m to reach his friend’s house. While returning, he walks diagonally from his friend’s house to reach back to his house. What distance did he walk while returning?
Advertisements
Solution
Let Rahul walked x m, while returning home.
In ΔABC, by using Pythagoras theorem, we get
AC2 = AB2 + BC2
⇒ AC2 = (12)2 + (35)2
⇒ AC2 = 144 + 1225 = 1369
⇒ AC = `sqrt(1369)`
⇒ AC = 37 m
| 37 | |
| 3 | `bar13` `bar69` |
| 9 | |
| 67 | 469 |
| 469 | |
| 0 |
Hence, Rahul walked 37 m distance for returning to his house diagonally.
APPEARS IN
RELATED QUESTIONS
Find the square of the given number.
86
Find the square of the given number.
71
Write a Pythagorean triplet whose one member is 16.
What will be the units digit of the square of the following number?
52
Which of the following triplet pythagorean?
(14, 48, 51)
Which of the following triplet pythagorean?
(12, 35, 38)
Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :
12 + 22 + 32 + 42 + ... + 102
Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication:
96
Find the square of the following number:
451
The dimensions of a rectangular field are 80 m and 18 m. Find the length of its diagonal.
