Advertisements
Advertisements
प्रश्न
Write a Pythagorean triplet whose one member is 14.
Advertisements
उत्तर
The three numbers of the Pythagorean triplet are 2m, m2 - 1, and m2 + 1.
Here, 2m = 14
so, m = 7
Second number (m2 - 1) = (7)2 - 1
= 49 - 1
= 48
Third number (m2 + 1) = (7)2 + 1
= 49 + 1
= 50
Hence the Pythagorean triplet is (14, 48, 50).
संबंधित प्रश्न
What will be the units digit of the square of the following number?
78367
What will be the units digit of the square of the following number?
52698
From the pattern, we can say that the sum of the first n positive odd numbers is equal to the square of the n-th positive number. Putting that into formula:
1 + 3 + 5 + 7 + ... n = n2, where the left hand side consists of n terms.
Which of the following triplet is pythagorean?
(18, 80, 82)
Which of the following number square of even number?
5476
Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication:
37
Find the squares of the following numbers using diagonal method:
98
Find a Pythagorean triplet in which one member is 12.
The sides of a right triangle whose hypotenuse is 17 cm are ______ and ______.
Put three different numbers in the circles so that when you add the numbers at the end of each line you always get a perfect square.
