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Karnataka Board PUCPUC Science Class 11

Wo Samples a and B, of the Same Gas Have Equal Volumes and Pressures. - Physics

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Question

Two samples A and B, of the same gas have equal volumes and pressures. The gas in sample A is expanded isothermally to double its volume and the gas in B is expanded adiabatically to double its volume. If the work done by the gas is the same for the two cases, show that γ satisfies the equation 1 − 21−γ = (γ − 1) ln2.

Answer in Brief
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Solution

Let,
Initial pressure of the gas = P1
Initial volume of the gas = V1 
Final pressure of the gas= P2 
Final volume of the gas = V2 
Given, V2 = 2 V1, for each case.
In an isothermal expansion process,
work done = `"n""R""T"_1   "l""n"  "V"_2/"V"_1" `

Adiabatic work done,

`"W" = ("P"_1"V"_1 - "P"_2"V"_2)/ (gamma -1 )`

It is given that same work is done in both cases.
So, 

`"n""R""T"_1   "l""n" ("V"_2/"V"_1) =( "P"_1 "V"_1 - "P"_2"V"_2)/ (gamma -1)` ..(1)

In an adiabatic process,

`"P"_2 = "P"_1 ("V"_1/"V"_2)^gamma ="P"_1(1/2)^gamma`

From eq (1),

`"n""R""T"_1  "l""n" 2 = ("P"_1"V"_1(1-1/2^gamma xx 2)) /(gamma -1)`

and nRT1 = P1V1

So, ln  2 =` (1 - 1/(2^gamma) . 2)/ (gamma -1)`

Or (γ − 1) ln 2 = 1 − 21−γ

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Interpretation of Temperature in Kinetic Theory - Introduction of Kinetic Theory of an Ideal Gas
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Chapter 5: Specific Heat Capacities of Gases - Exercises [Page 79]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 5 Specific Heat Capacities of Gases
Exercises | Q 24 | Page 79

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