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Karnataka Board PUCPUC Science Class 11

Let Q and W Denote the Amount of Heat Given to an Ideal Gas and the Work Done by It in an Adiabatic Process.

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Question

Let Q and W denote the amount of heat given to an ideal gas and the work done by it in an adiabatic process.
(a) Q = 0
(b) W = 0
(c) Q = W
(d) Q ≠ W

Answer in Brief
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Solution

(a) Q = 0
(d) Q ≠ W 
In an adiabatic process, no heat is supplied to the system; so, Q = 0. According to the first law of thermodynamics, heat given to any system is equal to the sum of the change in internal energy and the work done on the system. So, Q = W+U and as Q = 0, W = -U and  Q ≠ W.

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Interpretation of Temperature in Kinetic Theory - Introduction of Kinetic Theory of an Ideal Gas
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Chapter 27: Specific Heat Capacities of Gases - MCQ [Page 77]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 27 Specific Heat Capacities of Gases
MCQ | Q 3 | Page 77

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