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Without using trigonometric tables, prove that: tan^2 56° – cot^2 34° = 0

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Question

Without using trigonometric tables, prove that:

tan256° – cot234° = 0

Theorem
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Solution

Given: Let the angles 56° and 34° be as stated.

To Prove: tan256° – cot234° = 0

Proof [Step-wise]:

1. Note that 56° + 34° = 90°.

2. Use the complementary-angle identity cot θ = tan(90° – θ).

3. Apply the identity with θ = 34°:

cot 34° = tan(90° – 34°)

= tan 56°

4. Square both sides: cot234° = tan256°.

5. Rearranging gives: tan256° – cot234°

= tan256° – tan256°

= 0

tan256° – cot234° = 0, as required.

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Chapter 12: Trigonometric Ratios of Some Complemantary Angles - EXERCISE 12 [Page 590]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 12 Trigonometric Ratios of Some Complemantary Angles
EXERCISE 12 | Q 3. (iii) | Page 590
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