English

Without using trigonometric tables, prove that: sec^2 29° – cot^2 61° = 1

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Question

Without using trigonometric tables, prove that:

sec229° – cot261° = 1

Theorem
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Solution

Given: sec229° – cot261°

To Prove: sec229° – cot261° = 1

Proof [Step-wise]:

1. Note that 61° = 90° – 29°.

2. Using the complementary-angle identity cot(90° – A) = tan A, we get 

cot 61° = cot(90° – 29°) 

= tan 29°

3. Therefore cot261° = tan229°.

4. Substitute into the expression:

sec229° – cot261° = sec229° – tan229°

5. Use the Pythagorean identity sec2θ = 1 + tan2θ

So, sec229° – tan229° = 1.

Hence, sec229° – cot261° = 1.

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Chapter 12: Trigonometric Ratios of Some Complemantary Angles - EXERCISE 12 [Page 590]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 12 Trigonometric Ratios of Some Complemantary Angles
EXERCISE 12 | Q 3. (ii) | Page 590
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