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Question
Without using trigonometric tables, prove that:
cosec 80° − sec 10° = 0
Sum
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Solution
LHS = cosec 80° − sec 10°
= `"cosec" (90^circ - 10^circ) - sec 10^circ`
= `sec 10^circ - sec 10^circ`
= 0
= RHS
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