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Question
Without using trigonometric tables, prove that:
tan 71° – cot 19° = 0
Theorem
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Solution
LHS = tan 71° − cot 19°
= `tan (90^circ - 19^circ) - cot 19^circ`
= `cot 19^circ - cot 19^circ`
= 0
= RHS
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Chapter 12: Trigonometric Ratios of Some Complemantary Angles - EXERCISE 12 [Page 590]
