Question

Without solving, comment upon the nature of roots of the following equation: 

6x² – 13x + 4 = 0

Answer 1

6x² – 13x + 4 = 0

a = 6, b = −13 and c = 4

∴ Discriminant = b² – 4ac

= (−13)² – 4(6)(4)

= 169 – 96

= 73

Since 73 is not a perfect square, roots are irrational

Since D > 0, then equation has two real and unequal roots.