Question

With reference to the diagram shown below calculate:

(i) The equivalent resistance between P and Q.
(ii) The reading of ammeter.
(iii) The electrical power between P and Q.

Answer 1

(i) `1/"R" = 1/4 + 1/6 = (3 + 2)/12 = 5/12`

So, equivalent resistances

`= 12/5 = 2.4 Omega`

(ii) Here, R = 2.4 Ω

E = 2 × 2 = 4 V

From E = IR

I = `"E"/"R"`  or   I = `4/2.4 = 1.66` A

(iii) Power between P and Q

= I²R

= (1.66)² × (2.4) = 6.66 watts