Advertisements
Advertisements
Question
Why is potentiometer preferred over a voltmeter for comparison of emf. of cells?
Advertisements
Solution
Potentiometer is preferred over a voltmeter for comparison of emf of cells because of the following reasons:
(a) A potentiometer can measure the internal resistance of the cell, which a voltmeter cannot measure.
(b) A potentiometer can accurately measure small potential differences, which a voltmeter cannot.
(c) The accuracy of a potentiometer can also be increased by increasing the length of the wire, whereas the accuracy of the voltmeter is fixed.
APPEARS IN
RELATED QUESTIONS
In a series LCR circuit, what is the phase difference between VL and VC where VL is the potential difference across the inductor and V c is the potential difference across the capacitor?
The emf of a cell is always greater than its terminal voltage. Why? Give reason.
The potential difference between the terminals of a battery of emf 6.0 V and internal resistance 1 Ω drops to 5.8 V when connected across an external resistor. Find the resistance of the external resistor.
A voltmeter of resistance 400 Ω is used to measure the potential difference across the 100 Ω resistor in the circuit shown in the figure. (a) What will be the reading of the voltmeter? (b) What was the potential difference across 100 Ω before the voltmeter was connected?

A 6-volt battery of negligible internal resistance is connected across a uniform wire AB of length 100 cm. The positive terminal of another battery of emf 4 V and internal resistance 1 Ω is joined to the point A, as shown in the figure. Take the potential at B to be zero. (a) What are the potentials at the points A and C? (b) At which point D of the wire AB, the potential is equal to the potential at C? (c) If the points C and D are connected by a wire, what will be the current through it? (d) If the 4 V battery is replaced by a 7.5 V battery, what would be the answers of parts (a) and (b)?

The potential difference across the terminals of a battery of emf 12 V and internal resistance 2 Ω drops to 10 V when it is connected to a silver voltameter. Find the silver deposited at the cathode in half an hour. Atomic weight of silver is 107.9 g mol−1.
A potential difference of 220 V is maintained across 12000 Ω rheostat. Then voltmeter V has a resistance of 6000 Ω and point C is at one fourth the distance from a to b. Then the reading of voltmeter is ______.

Two sources of equal e.m.f are connected to an external resistance R in series. The internal resistance of the two sources are R1 and R2 (R2 > R1) If the potential difference across the source having internal. resistance R2 is zero, then ______.
