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Question
Which ratio defines the self-inductance of a coil using magnetic flux linkage?
Options
\[L=\frac{N\Phi_B}{I}\]
\[L=\frac{NI}{\Phi_B}\]
\[L=\frac{\Phi_B}{NI}\]
\[L=\frac{I}{N\Phi_B}\]
MCQ
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Solution
Self-inductance is the ratio of total magnetic flux linkage through the coil to the current flowing in it. For \[N\] turns, the total flux linkage is \[N\Phi_B\].
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