Question

Which ratio defines the self-inductance of a coil using magnetic flux linkage?

पर्याय

• \[L=\frac{N\Phi_B}{I}\]

• \[L=\frac{NI}{\Phi_B}\]

• \[L=\frac{\Phi_B}{NI}\]

• \[L=\frac{I}{N\Phi_B}\]

Answer 1

Self-inductance is the ratio of total magnetic flux linkage through the coil to the current flowing in it. For \[N\] turns, the total flux linkage is \[N\Phi_B\].