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Question
Which of the following equation depicts reducing nature of \[\ce{H2O2}\]?
Options
\[\ce{2[Fe(CN)6]^{4-} + 2H^{+} + H2O2 -> 2[Fe(CN)6]^{3-} + 2H2O}\]
\[\ce{I2 + H2O2 + 2OH^{-} -> 2I^{-} + 2H2O + O2}\]
\[\ce{Mn^{2+} + H2O2 -> Mn^{4+} + 2OH-}\]
\[\ce{PbS + 4H2O2 -> PbSO4 + 4H2O}\]
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Solution
\[\ce{I2 + H2O2 + 2OH^{-} -> 2I^{-} + 2H2O + O2}\]
Explanation:
As iodine is reduced from 0 to –1.
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