Advertisements
Advertisements
Question
Which of the following is not reciprocal of \[\left( \frac{2}{3} \right)^4 ?\]
Options
- \[\left( \frac{3}{2} \right)^4\]
- \[\left( \frac{2}{3} \right)^{- 4}\]
- \[\left( \frac{3}{2} \right)^{- 4}\]
- \[\frac{3^4}{2^4}\]
MCQ
Sum
Advertisements
Solution
\[\left( \frac{3}{2} \right)^{- 4}\]
The reciprocal of `(2/3)^4` is `(3/2)^4`
Therefore, option (a) is the correct answer.
Option (b) is just re-expressing the number with a negative exponent.
Option (d) is obtained by working out the exponent.
Hence,option (c) is not the reciprocal of `(2/3)^4`.
The reciprocal of `(2/3)^4` is `(3/2)^4`
Therefore, option (a) is the correct answer.
Option (b) is just re-expressing the number with a negative exponent.
Option (d) is obtained by working out the exponent.
Hence,option (c) is not the reciprocal of `(2/3)^4`.
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Evaluate.
`(5/8)^(-7) xx (8/5)^(-4)`
Simplify.
`(3^(-5) xx 10^(-5) xx 125)/(5^(-7) xx 6^(-5))`
Simplify:
\[\left\{ 4^{- 1} \times 3^{- 1} \right\}^2\]
Express the following rational numbers with a negative exponent:
\[\left( \frac{1}{4} \right)^3\]
Simplify:
\[\left( 3^2 - 2^2 \right) \times \left( \frac{2}{3} \right)^{- 3}\]
Simplify:
\[\left[ \left\{ \left( \frac{- 1}{4} \right)^2 \right\}^{- 2} \right]^{- 1}\]
By what number should \[\left( \frac{1}{2} \right)^{- 1}\] be multiplied so that the product may be equal to \[\left( \frac{- 4}{7} \right)^{- 1} ?\]
Find x, if
\[\left( \frac{- 1}{2} \right)^{- 19} \times \left( \frac{- 1}{2} \right)^8 = \left( \frac{- 1}{2} \right)^{- 2x + 1}\]
Find x, if
\[\left( \frac{2}{5} \right)^{- 3} \times \left( \frac{2}{5} \right)^{15} = \left( \frac{2}{5} \right)^{2 + 3x}\]
Find x, if
\[\left( \frac{5}{4} \right)^{- x} \div \left( \frac{5}{4} \right)^{- 4} = \left( \frac{5}{4} \right)^5\]
