Question

Which of the following are the roots of `3x^2+2x-1=0` 

`-1/2` 

 

Answer 1

On subtracting x=`(-1/2)` in the given equation, we get 
L.H.S=`3x^2+2x-1` 

=`3xx(-1/2)^2+2xx(-1/2)-1` 

`=3xx1/4-1-1` 

`=3/4-2` 

`-(3-8)/4` 

=-5/4≠ 0

Thus, L.H.S  R.H.S. 

Hence, (-1/2) is a solution of` (3x^2+2x-1=0)`