Question

Find the value of k for which x = 1is a root of the equation `x^2+kx+3=0` 

 

Answer 1

It is given that (x=1) is a root of `(x^2+kx+3=0)` 

Therefore, (x=1) must satisfy the equation. 

`⇒ (1)^2+kxx1+3=0` 

`⇒k+4=0` 

`⇒k=-4` 

Hence, the required value of k is -4.